413004013041 has 4 divisors (see below), whose sum is σ = 550672017392. Its totient is φ = 275336008692.

The previous prime is 413004012961. The next prime is 413004013043. The reversal of 413004013041 is 140310400314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 413004013041 - 2¹⁵ = 413003980273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 413004012999 and 413004013017.

It is not an unprimeable number, because it can be changed into a prime (413004013043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68834002171 + ... + 68834002176.

It is an arithmetic number, because the mean of its divisors is an integer number (137668004348).

Almost surely, 2^413004013041 is an apocalyptic number.

It is an amenable number.

413004013041 is a deficient number, since it is larger than the sum of its proper divisors (137668004351).

413004013041 is a wasteful number, since it uses less digits than its factorization.

413004013041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137668004350.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 413004013041 its reverse (140310400314), we get a palindrome (553314413355).

The spelling of 413004013041 in words is "four hundred thirteen billion, four million, thirteen thousand, forty-one".