Base | Representation |
---|---|
bin | 1100000001010001111… |
… | …10100010000010011011 |
3 | 1110111000222112100202000 |
4 | 12000220332202002123 |
5 | 23231313102411103 |
6 | 513422004212043 |
7 | 41560426656543 |
oct | 6005076420233 |
9 | 1414028470660 |
10 | 413004341403 |
11 | 14a177202595 |
12 | 6806239a023 |
13 | 2cc3b8a0104 |
14 | 15dbd33c323 |
15 | ab23406aa3 |
hex | 6028fa209b |
413004341403 has 8 divisors (see below), whose sum is σ = 611858283600. Its totient is φ = 275336227584.
The previous prime is 413004341371. The next prime is 413004341441. The reversal of 413004341403 is 304143400314.
It is not a de Polignac number, because 413004341403 - 25 = 413004341371 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 15296457089 = 413004341403 / (4 + 1 + 3 + 0 + 0 + 4 + 3 + 4 + 1 + 4 + 0 + 3).
It is not an unprimeable number, because it can be changed into a prime (413004341473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7648228518 + ... + 7648228571.
It is an arithmetic number, because the mean of its divisors is an integer number (76482285450).
Almost surely, 2413004341403 is an apocalyptic number.
413004341403 is a deficient number, since it is larger than the sum of its proper divisors (198853942197).
413004341403 is a wasteful number, since it uses less digits than its factorization.
413004341403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15296457098 (or 15296457092 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 413004341403 its reverse (304143400314), we get a palindrome (717147741717).
The spelling of 413004341403 in words is "four hundred thirteen billion, four million, three hundred forty-one thousand, four hundred three".
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