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41301113 = 74323191
BaseRepresentation
bin1001110110001…
…1010001111001
32212201022110212
42131203101321
541033113423
64033120505
71011024260
oct235432171
985638425
1041301113
112134a157
12119b9135
138730b39
1456b15d7
15395c578
hex2763479

41301113 has 12 divisors (see below), whose sum is σ = 48339648. Its totient is φ = 34566840.

The previous prime is 41301107. The next prime is 41301119. The reversal of 41301113 is 31110314.

It is an interprime number because it is at equal distance from previous prime (41301107) and next prime (41301119).

It is not a de Polignac number, because 41301113 - 24 = 41301097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (41301119) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11348 + ... + 14538.

It is an arithmetic number, because the mean of its divisors is an integer number (4028304).

Almost surely, 241301113 is an apocalyptic number.

41301113 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

41301113 is a deficient number, since it is larger than the sum of its proper divisors (7038535).

41301113 is an equidigital number, since it uses as much as digits as its factorization.

41301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3284 (or 3241 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 41301113 is about 6426.5941991073. The cubic root of 41301113 is about 345.6638147022.

Adding to 41301113 its reverse (31110314), we get a palindrome (72411427).

It can be divided in two parts, 41301 and 113, that added together give a palindrome (41414).

The spelling of 41301113 in words is "forty-one million, three hundred one thousand, one hundred thirteen".

Divisors: 1 7 43 301 1849 3191 12943 22337 137213 960491 5900159 41301113