Base | Representation |
---|---|
bin | 101110111101000011010101… |
… | …0101001010111101011000001 |
3 | 2000011100111010120020021102001 |
4 | 1131322012222221113223001 |
5 | 413113233431024402431 |
6 | 4022222422035424001 |
7 | 152665034610446356 |
oct | 13572065251275301 |
9 | 2004314116207361 |
10 | 413011213122241 |
11 | 10a66408769a068 |
12 | 3a3a440b755001 |
13 | 1495ba37330836 |
14 | 73dbbc697a62d |
15 | 32b3581e01e61 |
hex | 177a1aaa57ac1 |
413011213122241 has 2 divisors, whose sum is σ = 413011213122242. Its totient is φ = 413011213122240.
The previous prime is 413011213122227. The next prime is 413011213122367. The reversal of 413011213122241 is 142221312110314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 262617290331841 + 150393922790400 = 16205471^2 + 12263520^2 .
It is a cyclic number.
It is not a de Polignac number, because 413011213122241 - 27 = 413011213122113 is a prime.
It is not a weakly prime, because it can be changed into another prime (413011253122241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206505606561120 + 206505606561121.
It is an arithmetic number, because the mean of its divisors is an integer number (206505606561121).
Almost surely, 2413011213122241 is an apocalyptic number.
It is an amenable number.
413011213122241 is a deficient number, since it is larger than the sum of its proper divisors (1).
413011213122241 is an equidigital number, since it uses as much as digits as its factorization.
413011213122241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 413011213122241 its reverse (142221312110314), we get a palindrome (555232525232555).
The spelling of 413011213122241 in words is "four hundred thirteen trillion, eleven billion, two hundred thirteen million, one hundred twenty-two thousand, two hundred forty-one".
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