413011300514433 has 8 divisors (see below), whose sum is σ = 550681831650048. Its totient is φ = 275340818194224.

The previous prime is 413011300514419. The next prime is 413011300514441. The reversal of 413011300514433 is 334415003110314.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 413011300514433 - 2¹⁷ = 413011300383361 is a prime.

It is a super-2 number, since 2×413011300514433² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 413011300514394 and 413011300514403.

It is not an unprimeable number, because it can be changed into a prime (413011300514443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18763216 + ... + 34323182.

It is an arithmetic number, because the mean of its divisors is an integer number (68835228956256).

Almost surely, 2^{413011300514433} is an apocalyptic number.

It is an amenable number.

413011300514433 is a deficient number, since it is larger than the sum of its proper divisors (137670531135615).

413011300514433 is a wasteful number, since it uses less digits than its factorization.

413011300514433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24407703.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 413011300514433 its reverse (334415003110314), we get a palindrome (747426303624747).

The spelling of 413011300514433 in words is "four hundred thirteen trillion, eleven billion, three hundred million, five hundred fourteen thousand, four hundred thirty-three".