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413020244113 is a prime number
BaseRepresentation
bin1100000001010011110…
…11001100100010010001
31110111002002110022011021
412000221323030202101
523231331140302423
6513423333115441
741561012102251
oct6005173144221
91414062408137
10413020244113
1114a185184524
1268067788b81
132cc41c7a5b9
1415dc14bb961
15ab249e895d
hex6029ecc891

413020244113 has 2 divisors, whose sum is σ = 413020244114. Its totient is φ = 413020244112.

The previous prime is 413020244101. The next prime is 413020244123. The reversal of 413020244113 is 311442020314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 406651086864 + 6369157249 = 637692^2 + 79807^2 .

It is a cyclic number.

It is not a de Polignac number, because 413020244113 - 25 = 413020244081 is a prime.

It is a super-3 number, since 3×4130202441133 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (413020244123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206510122056 + 206510122057.

It is an arithmetic number, because the mean of its divisors is an integer number (206510122057).

Almost surely, 2413020244113 is an apocalyptic number.

It is an amenable number.

413020244113 is a deficient number, since it is larger than the sum of its proper divisors (1).

413020244113 is an equidigital number, since it uses as much as digits as its factorization.

413020244113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 413020244113 its reverse (311442020314), we get a palindrome (724462264427).

The spelling of 413020244113 in words is "four hundred thirteen billion, twenty million, two hundred forty-four thousand, one hundred thirteen".