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413043310224323 is a prime number
BaseRepresentation
bin101110111101010010010001…
…1110010000110001111000011
32000011110112222110121000000122
41131322210203302012033003
5413114300144404134243
64022245251024010455
7153000252163352432
oct13572444362061703
92004415873530018
10413043310224323
1110a676758671a09
123a3aa688a60a2b
1314961a8100a72c
1473dd58d719119
1532b430ebbe668
hex177a923c863c3

413043310224323 has 2 divisors, whose sum is σ = 413043310224324. Its totient is φ = 413043310224322.

The previous prime is 413043310224299. The next prime is 413043310224343. The reversal of 413043310224323 is 323422013340314.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-413043310224323 is a prime.

It is a super-3 number, since 3×4130433102243233 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (413043310224343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206521655112161 + 206521655112162.

It is an arithmetic number, because the mean of its divisors is an integer number (206521655112162).

Almost surely, 2413043310224323 is an apocalyptic number.

413043310224323 is a deficient number, since it is larger than the sum of its proper divisors (1).

413043310224323 is an equidigital number, since it uses as much as digits as its factorization.

413043310224323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 413043310224323 its reverse (323422013340314), we get a palindrome (736465323564637).

The spelling of 413043310224323 in words is "four hundred thirteen trillion, forty-three billion, three hundred ten million, two hundred twenty-four thousand, three hundred twenty-three".