Base | Representation |
---|---|
bin | 100110011101111011… |
… | …100001011101100011 |
3 | 10221121120101110210221 |
4 | 212131323201131203 |
5 | 1134042402112011 |
6 | 30550331103511 |
7 | 2661363013246 |
oct | 463573413543 |
9 | 127546343727 |
10 | 41304332131 |
11 | 16576245087 |
12 | 80088a1b97 |
13 | 3b8337631a |
14 | 1ddb8d925d |
15 | 111b280971 |
hex | 99dee1763 |
41304332131 has 2 divisors, whose sum is σ = 41304332132. Its totient is φ = 41304332130.
The previous prime is 41304332117. The next prime is 41304332159. The reversal of 41304332131 is 13123340314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41304332131 - 223 = 41295943523 is a prime.
It is a super-2 number, since 2×413043321312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41304332096 and 41304332105.
It is not a weakly prime, because it can be changed into another prime (41304392131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20652166065 + 20652166066.
It is an arithmetic number, because the mean of its divisors is an integer number (20652166066).
Almost surely, 241304332131 is an apocalyptic number.
41304332131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41304332131 is an equidigital number, since it uses as much as digits as its factorization.
41304332131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 41304332131 its reverse (13123340314), we get a palindrome (54427672445).
The spelling of 41304332131 in words is "forty-one billion, three hundred four million, three hundred thirty-two thousand, one hundred thirty-one".
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