413101121 has 2 divisors, whose sum is σ = 413101122. Its totient is φ = 413101120.

The previous prime is 413101099. The next prime is 413101141. The reversal of 413101121 is 121101314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 377758096 + 35343025 = 19436^2 + 5945^2 .

It is a cyclic number.

It is not a de Polignac number, because 413101121 - 2⁶ = 413101057 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 413101096 and 413101105.

It is not a weakly prime, because it can be changed into another prime (413101141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206550560 + 206550561.

It is an arithmetic number, because the mean of its divisors is an integer number (206550561).

Almost surely, 2^413101121 is an apocalyptic number.

It is an amenable number.

413101121 is a deficient number, since it is larger than the sum of its proper divisors (1).

413101121 is an equidigital number, since it uses as much as digits as its factorization.

413101121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 413101121 is about 20324.8892001900. The cubic root of 413101121 is about 744.7641978537.

Adding to 413101121 its reverse (121101314), we get a palindrome (534202435).

The spelling of 413101121 in words is "four hundred thirteen million, one hundred one thousand, one hundred twenty-one".