413112103113 has 4 divisors (see below), whose sum is σ = 550816137488. Its totient is φ = 275408068740.

The previous prime is 413112103069. The next prime is 413112103121. The reversal of 413112103113 is 311301211314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 413112103113 - 2¹⁷ = 413111972041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 413112103113.

It is not an unprimeable number, because it can be changed into a prime (413112103153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68852017183 + ... + 68852017188.

It is an arithmetic number, because the mean of its divisors is an integer number (137704034372).

Almost surely, 2^413112103113 is an apocalyptic number.

It is an amenable number.

413112103113 is a deficient number, since it is larger than the sum of its proper divisors (137704034375).

413112103113 is a wasteful number, since it uses less digits than its factorization.

413112103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137704034374.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 413112103113 its reverse (311301211314), we get a palindrome (724413314427).

The spelling of 413112103113 in words is "four hundred thirteen billion, one hundred twelve million, one hundred three thousand, one hundred thirteen".