413124131000401 has 4 divisors (see below), whose sum is σ = 427369790690100. Its totient is φ = 398878471310704.

The previous prime is 413124131000311. The next prime is 413124131000423. The reversal of 413124131000401 is 104000131421314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 167387186352400 + 245736944648001 = 12937820^2 + 15675999^2 .

It is a cyclic number.

It is not a de Polignac number, because 413124131000401 - 2⁹ = 413124130999889 is a prime.

It is a super-2 number, since 2×413124131000401² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413124134000401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7122829844806 + ... + 7122829844863.

It is an arithmetic number, because the mean of its divisors is an integer number (106842447672525).

Almost surely, 2^{413124131000401} is an apocalyptic number.

It is an amenable number.

413124131000401 is a deficient number, since it is larger than the sum of its proper divisors (14245659689699).

413124131000401 is a wasteful number, since it uses less digits than its factorization.

413124131000401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14245659689698.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 413124131000401 its reverse (104000131421314), we get a palindrome (517124262421715).

The spelling of 413124131000401 in words is "four hundred thirteen trillion, one hundred twenty-four billion, one hundred thirty-one million, four hundred one", and thus it is an aban number.