413140153115441 has 4 divisors (see below), whose sum is σ = 413202009710400. Its totient is φ = 413078296520484.

The previous prime is 413140153115411. The next prime is 413140153115509. The reversal of 413140153115441 is 144511351041314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 413140153115441 - 2³⁰ = 413139079373617 is a prime.

It is a super-3 number, since 3×413140153115441³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 413140153115395 and 413140153115404.

It is not an unprimeable number, because it can be changed into a prime (413140153115411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30928287461 + ... + 30928300818.

It is an arithmetic number, because the mean of its divisors is an integer number (103300502427600).

Almost surely, 2^{413140153115441} is an apocalyptic number.

It is an amenable number.

413140153115441 is a deficient number, since it is larger than the sum of its proper divisors (61856594959).

413140153115441 is an equidigital number, since it uses as much as digits as its factorization.

413140153115441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61856594958.

The product of its (nonzero) digits is 57600, while the sum is 38.

The spelling of 413140153115441 in words is "four hundred thirteen trillion, one hundred forty billion, one hundred fifty-three million, one hundred fifteen thousand, four hundred forty-one".