Base | Representation |
---|---|
bin | 10010110010100100000101… |
… | …11010100100011111001011 |
3 | 12102022010120122011222102001 |
4 | 21121102002322210133023 |
5 | 20403440403113420103 |
6 | 223514013512051431 |
7 | 11463153466056361 |
oct | 1131220272443713 |
9 | 172263518158361 |
10 | 41319781779403 |
11 | 12190691678986 |
12 | 4774073393b77 |
13 | 1a09591aa2cca |
14 | a2bc60d83631 |
15 | 4b9c5065501d |
hex | 259482ea47cb |
41319781779403 has 2 divisors, whose sum is σ = 41319781779404. Its totient is φ = 41319781779402.
The previous prime is 41319781779383. The next prime is 41319781779407. The reversal of 41319781779403 is 30497718791314.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41319781779403 is a prime.
It is not a weakly prime, because it can be changed into another prime (41319781779407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20659890889701 + 20659890889702.
It is an arithmetic number, because the mean of its divisors is an integer number (20659890889702).
Almost surely, 241319781779403 is an apocalyptic number.
41319781779403 is a deficient number, since it is larger than the sum of its proper divisors (1).
41319781779403 is an equidigital number, since it uses as much as digits as its factorization.
41319781779403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32006016, while the sum is 64.
The spelling of 41319781779403 in words is "forty-one trillion, three hundred nineteen billion, seven hundred eighty-one million, seven hundred seventy-nine thousand, four hundred three".
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