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41321040217 is a prime number
BaseRepresentation
bin100110011110111011…
…010000100101011001
310221122201211022222221
4212132323100211121
51134111141241332
630552125144041
72661655022002
oct463673204531
9127581738887
1041321040217
1116584717116
1280123bb021
133b86976272
141dddc081a9
15111c981297
hex99eed0959

41321040217 has 2 divisors, whose sum is σ = 41321040218. Its totient is φ = 41321040216.

The previous prime is 41321040203. The next prime is 41321040263. The reversal of 41321040217 is 71204012314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40731716041 + 589324176 = 201821^2 + 24276^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41321040217 is a prime.

It is a super-2 number, since 2×413210402172 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41321040191 and 41321040200.

It is not a weakly prime, because it can be changed into another prime (41321040617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20660520108 + 20660520109.

It is an arithmetic number, because the mean of its divisors is an integer number (20660520109).

Almost surely, 241321040217 is an apocalyptic number.

It is an amenable number.

41321040217 is a deficient number, since it is larger than the sum of its proper divisors (1).

41321040217 is an equidigital number, since it uses as much as digits as its factorization.

41321040217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

The spelling of 41321040217 in words is "forty-one billion, three hundred twenty-one million, forty thousand, two hundred seventeen".