Base | Representation |
---|---|
bin | 1100000001101010100… |
… | …00100110000110101001 |
3 | 1110111120100021101102221 |
4 | 12000311100212012221 |
5 | 23232223330400431 |
6 | 513454244554041 |
7 | 41565511322116 |
oct | 6006520460651 |
9 | 1414510241387 |
10 | 413210403241 |
11 | 14a272555929 |
12 | 680bb3b2921 |
13 | 2cc7249a5ac |
14 | 15ddc85b90d |
15 | ab3655c111 |
hex | 60354261a9 |
413210403241 has 4 divisors (see below), whose sum is σ = 413394956800. Its totient is φ = 413025849684.
The previous prime is 413210403239. The next prime is 413210403247. The reversal of 413210403241 is 142304012314.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 413210403241 - 21 = 413210403239 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (413210403247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92273421 + ... + 92277898.
It is an arithmetic number, because the mean of its divisors is an integer number (103348739200).
Almost surely, 2413210403241 is an apocalyptic number.
It is an amenable number.
413210403241 is a deficient number, since it is larger than the sum of its proper divisors (184553559).
413210403241 is a wasteful number, since it uses less digits than its factorization.
413210403241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 184553558.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 413210403241 its reverse (142304012314), we get a palindrome (555514415555).
The spelling of 413210403241 in words is "four hundred thirteen billion, two hundred ten million, four hundred three thousand, two hundred forty-one".
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