Base | Representation |
---|---|
bin | 1111011001001110… |
… | …0110101000100001 |
3 | 101122222201022201121 |
4 | 3312103212220201 |
5 | 31430334142423 |
6 | 1522014132241 |
7 | 204255155215 |
oct | 36623465041 |
9 | 11588638647 |
10 | 4132334113 |
11 | 183065a866 |
12 | 973ab1081 |
13 | 50b17671b |
14 | 2b2b60945 |
15 | 192bb545d |
hex | f64e6a21 |
4132334113 has 2 divisors, whose sum is σ = 4132334114. Its totient is φ = 4132334112.
The previous prime is 4132334081. The next prime is 4132334179. The reversal of 4132334113 is 3114332314.
4132334113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3130738209 + 1001595904 = 55953^2 + 31648^2 .
It is a cyclic number.
It is not a de Polignac number, because 4132334113 - 25 = 4132334081 is a prime.
It is not a weakly prime, because it can be changed into another prime (4132334413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066167056 + 2066167057.
It is an arithmetic number, because the mean of its divisors is an integer number (2066167057).
Almost surely, 24132334113 is an apocalyptic number.
It is an amenable number.
4132334113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4132334113 is an equidigital number, since it uses as much as digits as its factorization.
4132334113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 25.
The square root of 4132334113 is about 64283.2335294360. The cubic root of 4132334113 is about 1604.7170838304.
Adding to 4132334113 its reverse (3114332314), we get a palindrome (7246666427).
The spelling of 4132334113 in words is "four billion, one hundred thirty-two million, three hundred thirty-four thousand, one hundred thirteen".
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