Base | Representation |
---|---|
bin | 101110111110101111011101… |
… | …0000100011111101110100001 |
3 | 2000012011200110002001010112112 |
4 | 1131331132322010133232201 |
5 | 413131034440413002340 |
6 | 4022521221445005105 |
7 | 153020564455430516 |
oct | 13575367204375641 |
9 | 2005150402033475 |
10 | 413243400125345 |
11 | 10a7435a6157079 |
12 | 3a42140a6b3795 |
13 | 149778bab4577a |
14 | 740913171d30d |
15 | 32b9620ea1065 |
hex | 177d7ba11fba1 |
413243400125345 has 16 divisors (see below), whose sum is σ = 496595797221888. Its totient is φ = 330125614969920.
The previous prime is 413243400125273. The next prime is 413243400125473. The reversal of 413243400125345 is 543521004342314.
It is not a de Polignac number, because 413243400125345 - 228 = 413243131689889 is a prime.
It is a super-2 number, since 2×4132434001253452 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81459155 + ... + 86383335.
It is an arithmetic number, because the mean of its divisors is an integer number (31037237326368).
Almost surely, 2413243400125345 is an apocalyptic number.
It is an amenable number.
413243400125345 is a deficient number, since it is larger than the sum of its proper divisors (83352397096543).
413243400125345 is a wasteful number, since it uses less digits than its factorization.
413243400125345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4948000.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 413243400125345 its reverse (543521004342314), we get a palindrome (956764404467659).
The spelling of 413243400125345 in words is "four hundred thirteen trillion, two hundred forty-three billion, four hundred million, one hundred twenty-five thousand, three hundred forty-five".
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