413304514433 has 4 divisors (see below), whose sum is σ = 423385112388. Its totient is φ = 403223916480.

The previous prime is 413304514411. The next prime is 413304514453. The reversal of 413304514433 is 334415403314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 116292594289 + 297011920144 = 341017^2 + 544988^2 .

It is a cyclic number.

It is not a de Polignac number, because 413304514433 - 2³⁶ = 344585037697 is a prime.

It is a super-2 number, since 2×413304514433² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 413304514393 and 413304514402.

It is not an unprimeable number, because it can be changed into a prime (413304514453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5040298916 + ... + 5040298997.

It is an arithmetic number, because the mean of its divisors is an integer number (105846278097).

Almost surely, 2^413304514433 is an apocalyptic number.

It is an amenable number.

413304514433 is a deficient number, since it is larger than the sum of its proper divisors (10080597955).

413304514433 is a wasteful number, since it uses less digits than its factorization.

413304514433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10080597954.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 413304514433 its reverse (334415403314), we get a palindrome (747719917747).

The spelling of 413304514433 in words is "four hundred thirteen billion, three hundred four million, five hundred fourteen thousand, four hundred thirty-three".