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413314440113 is a prime number
BaseRepresentation
bin1100000001110110111…
…01011101101110110001
31110111211121001000012102
412000323131131232301
523232431444040423
6513512442510145
741601213526451
oct6007335355661
91414747030172
10413314440113
1114a316254313
126812a205355
132cc8abc5683
141600c5bdd61
15ab4075cc28
hex603b75dbb1

413314440113 has 2 divisors, whose sum is σ = 413314440114. Its totient is φ = 413314440112.

The previous prime is 413314440107. The next prime is 413314440131. The reversal of 413314440113 is 311044413314.

Together with next prime (413314440131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 314779346704 + 98535093409 = 561052^2 + 313903^2 .

It is a cyclic number.

It is not a de Polignac number, because 413314440113 - 214 = 413314423729 is a prime.

It is not a weakly prime, because it can be changed into another prime (413314440103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206657220056 + 206657220057.

It is an arithmetic number, because the mean of its divisors is an integer number (206657220057).

Almost surely, 2413314440113 is an apocalyptic number.

It is an amenable number.

413314440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

413314440113 is an equidigital number, since it uses as much as digits as its factorization.

413314440113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 413314440113 its reverse (311044413314), we get a palindrome (724358853427).

The spelling of 413314440113 in words is "four hundred thirteen billion, three hundred fourteen million, four hundred forty thousand, one hundred thirteen".