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4133211121132 = 221977977697441
BaseRepresentation
bin111100001001010110100…
…101001010010111101100
3112122010112120220210122021
4330021112211022113230
51020204304021334012
612442434310355524
7604420552566502
oct74112645122754
915563476823567
104133211121132
111353980a1a615
1256906405bba4
1323c9b6033a32
1410409708a672
15727aabb7007
hex3c25694a5ec

4133211121132 has 24 divisors (see below), whose sum is σ = 7613918518640. Its totient is φ = 1957808931840.

The previous prime is 4133211121103. The next prime is 4133211121157. The reversal of 4133211121132 is 2311211123314.

4133211121132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×41332111211322 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4133211121097 and 4133211121106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5577532 + ... + 6274972.

Almost surely, 24133211121132 is an apocalyptic number.

It is an amenable number.

4133211121132 is a deficient number, since it is larger than the sum of its proper divisors (3480707397508).

4133211121132 is a wasteful number, since it uses less digits than its factorization.

4133211121132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 775441 (or 775439 counting only the distinct ones).

The product of its digits is 864, while the sum is 25.

Adding to 4133211121132 its reverse (2311211123314), we get a palindrome (6444422244446).

The spelling of 4133211121132 in words is "four trillion, one hundred thirty-three billion, two hundred eleven million, one hundred twenty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 19 38 76 77977 155954 311908 697441 1394882 1481563 2789764 2963126 5926252 13251379 26502758 53005516 54384356857 108768713714 217537427428 1033302780283 2066605560566 4133211121132