Base | Representation |
---|---|
bin | 101110111111111001000010… |
… | …0011000111110011100101011 |
3 | 2000012201210022021201211012221 |
4 | 1131333302010120332130223 |
5 | 413141132043302024342 |
6 | 4023121553144014511 |
7 | 153035160255403033 |
oct | 13577620430763453 |
9 | 2005653267654187 |
10 | 413401413314347 |
11 | 10a7a4611510777 |
12 | 3a447b68a61437 |
13 | 149897805a5283 |
14 | 7412a4140c8c3 |
15 | 32bd7bd2d3a67 |
hex | 177fc8463e72b |
413401413314347 has 2 divisors, whose sum is σ = 413401413314348. Its totient is φ = 413401413314346.
The previous prime is 413401413314299. The next prime is 413401413314431. The reversal of 413401413314347 is 743413314104314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 413401413314347 - 223 = 413401404925739 is a prime.
It is not a weakly prime, because it can be changed into another prime (413401413014347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206700706657173 + 206700706657174.
It is an arithmetic number, because the mean of its divisors is an integer number (206700706657174).
Almost surely, 2413401413314347 is an apocalyptic number.
413401413314347 is a deficient number, since it is larger than the sum of its proper divisors (1).
413401413314347 is an equidigital number, since it uses as much as digits as its factorization.
413401413314347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 43.
The spelling of 413401413314347 in words is "four hundred thirteen trillion, four hundred one billion, four hundred thirteen million, three hundred fourteen thousand, three hundred forty-seven".
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