Base | Representation |
---|---|
bin | 10010110011001011111000… |
… | …01010101110010101011011 |
3 | 12102101011201100212020201001 |
4 | 21121211330022232111123 |
5 | 20404313130203110021 |
6 | 223531505322005431 |
7 | 11464541033661664 |
oct | 1131457412562533 |
9 | 172334640766631 |
10 | 41341143410011 |
11 | 1219975376a155 |
12 | 4778235346877 |
13 | 1a0b5b75b3b13 |
14 | a2ccca03036b |
15 | 4ba5a0bd7091 |
hex | 25997c2ae55b |
41341143410011 has 4 divisors (see below), whose sum is σ = 41341194091912. Its totient is φ = 41341092728112.
The previous prime is 41341143409963. The next prime is 41341143410029. The reversal of 41341143410011 is 11001434114314.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41341143410011 - 243 = 32545050387803 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41341143410041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24097050 + ... + 25755583.
It is an arithmetic number, because the mean of its divisors is an integer number (10335298522978).
Almost surely, 241341143410011 is an apocalyptic number.
41341143410011 is a deficient number, since it is larger than the sum of its proper divisors (50681901).
41341143410011 is an equidigital number, since it uses as much as digits as its factorization.
41341143410011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50681900.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 41341143410011 its reverse (11001434114314), we get a palindrome (52342577524325).
The spelling of 41341143410011 in words is "forty-one trillion, three hundred forty-one billion, one hundred forty-three million, four hundred ten thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •