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41343131022001 is a prime number
BaseRepresentation
bin10010110011001111100101…
…01000110111001010110001
312102101100211212220101202221
421121213302220313022301
520404331213020201001
6223532434443241041
711464641220260064
oct1131476250671261
9172340755811687
1041343131022001
111219a583715496
1247786aab19181
131a0b8433116a3
14a2d037dc28db
154ba66a44e1a1
hex2599f2a372b1

41343131022001 has 2 divisors, whose sum is σ = 41343131022002. Its totient is φ = 41343131022000.

The previous prime is 41343131021987. The next prime is 41343131022007. The reversal of 41343131022001 is 10022013134314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40564148262001 + 778982760000 = 6368999^2 + 882600^2 .

It is a cyclic number.

It is not a de Polignac number, because 41343131022001 - 221 = 41343128924849 is a prime.

It is a super-3 number, since 3×413431310220013 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (41343131022007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20671565511000 + 20671565511001.

It is an arithmetic number, because the mean of its divisors is an integer number (20671565511001).

Almost surely, 241343131022001 is an apocalyptic number.

It is an amenable number.

41343131022001 is a deficient number, since it is larger than the sum of its proper divisors (1).

41343131022001 is an equidigital number, since it uses as much as digits as its factorization.

41343131022001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 41343131022001 its reverse (10022013134314), we get a palindrome (51365144156315).

The spelling of 41343131022001 in words is "forty-one trillion, three hundred forty-three billion, one hundred thirty-one million, twenty-two thousand, one".