4134744474313 has 4 divisors (see below), whose sum is σ = 4352362604560. Its totient is φ = 3917126344068.

The previous prime is 4134744474293. The next prime is 4134744474317. The reversal of 4134744474313 is 3134744474314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4134744474313 - 2¹⁷ = 4134744343241 is a prime.

It is a super-2 number, since 2×4134744474313² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4134744474317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108809065095 + ... + 108809065132.

It is an arithmetic number, because the mean of its divisors is an integer number (1088090651140).

Almost surely, 2^{4134744474313} is an apocalyptic number.

It is an amenable number.

4134744474313 is a deficient number, since it is larger than the sum of its proper divisors (217618130247).

4134744474313 is a wasteful number, since it uses less digits than its factorization.

4134744474313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 217618130246.

The product of its digits is 5419008, while the sum is 49.

Subtracting from 4134744474313 its reverse (3134744474314), we obtain a palindrome (999999999999).

The spelling of 4134744474313 in words is "four trillion, one hundred thirty-four billion, seven hundred forty-four million, four hundred seventy-four thousand, three hundred thirteen".