Base | Representation |
---|---|
bin | 1100000010001110101… |
… | …00101111100000111011 |
3 | 1110112100110120021221101 |
4 | 12001013110233200323 |
5 | 23233333422332001 |
6 | 513544312552231 |
7 | 41606151405424 |
oct | 6010724574073 |
9 | 1415313507841 |
10 | 413513480251 |
11 | 14a4086410a3 |
12 | 681849b2677 |
13 | 2ccc0204ac1 |
14 | 1602abd264b |
15 | ab52e77a01 |
hex | 604752f83b |
413513480251 has 2 divisors, whose sum is σ = 413513480252. Its totient is φ = 413513480250.
The previous prime is 413513480189. The next prime is 413513480269. The reversal of 413513480251 is 152084315314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 413513480251 - 225 = 413479925819 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 413513480251.
It is not a weakly prime, because it can be changed into another prime (413513480291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206756740125 + 206756740126.
It is an arithmetic number, because the mean of its divisors is an integer number (206756740126).
Almost surely, 2413513480251 is an apocalyptic number.
413513480251 is a deficient number, since it is larger than the sum of its proper divisors (1).
413513480251 is an equidigital number, since it uses as much as digits as its factorization.
413513480251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 413513480251 its reverse (152084315314), we get a palindrome (565597795565).
The spelling of 413513480251 in words is "four hundred thirteen billion, five hundred thirteen million, four hundred eighty thousand, two hundred fifty-one".
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