413543511325121 has 4 divisors (see below), whose sum is σ = 413625579897600. Its totient is φ = 413461442752644.

The previous prime is 413543511325097. The next prime is 413543511325123. The reversal of 413543511325121 is 121523115345314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-413543511325121 is a prime.

It is a super-2 number, since 2×413543511325121² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413543511325123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41034278681 + ... + 41034288758.

It is an arithmetic number, because the mean of its divisors is an integer number (103406394974400).

Almost surely, 2^{413543511325121} is an apocalyptic number.

It is an amenable number.

413543511325121 is a deficient number, since it is larger than the sum of its proper divisors (82068572479).

413543511325121 is an equidigital number, since it uses as much as digits as its factorization.

413543511325121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82068572478.

The product of its digits is 216000, while the sum is 41.

The spelling of 413543511325121 in words is "four hundred thirteen trillion, five hundred forty-three billion, five hundred eleven million, three hundred twenty-five thousand, one hundred twenty-one".