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4136147640577 = 19217691981083
BaseRepresentation
bin111100001100000101100…
…111000110000100000001
3112122102010020111110000201
4330030011213012010001
51020231312243444302
612444041530245201
7604553410600621
oct74140547060401
915572106443021
104136147640577
111355148572097
12569743586801
1324006351ccc4
1410429508a881
15728cd8bbc87
hex3c3059c6101

4136147640577 has 4 divisors (see below), whose sum is σ = 4353839621680. Its totient is φ = 3918455659476.

The previous prime is 4136147640571. The next prime is 4136147640593. The reversal of 4136147640577 is 7750467416314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4136147640577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4136147640571) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108845990523 + ... + 108845990560.

It is an arithmetic number, because the mean of its divisors is an integer number (1088459905420).

Almost surely, 24136147640577 is an apocalyptic number.

It is an amenable number.

4136147640577 is a deficient number, since it is larger than the sum of its proper divisors (217691981103).

4136147640577 is a wasteful number, since it uses less digits than its factorization.

4136147640577 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 217691981102.

The product of its (nonzero) digits is 11854080, while the sum is 55.

The spelling of 4136147640577 in words is "four trillion, one hundred thirty-six billion, one hundred forty-seven million, six hundred forty thousand, five hundred seventy-seven".

Divisors: 1 19 217691981083 4136147640577