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414013025421241 is a prime number
BaseRepresentation
bin101111000100010101110101…
…1010100000000011110111001
32000021220020222120211000202021
41132020223223110000132321
5413231142134001434431
64024310542550034441
7153130311502466101
oct13610535324003671
92007806876730667
10414013025421241
1110aa0aa3560a024
123a5265b8648a21
1314a02350c0453c
1474344a197c201
1532ce667800b11
hex1788aeb5007b9

414013025421241 has 2 divisors, whose sum is σ = 414013025421242. Its totient is φ = 414013025421240.

The previous prime is 414013025421139. The next prime is 414013025421253. The reversal of 414013025421241 is 142124520310414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 391850774438841 + 22162250982400 = 19795221^2 + 4707680^2 .

It is a cyclic number.

It is not a de Polignac number, because 414013025421241 - 237 = 413875586467769 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 414013025421197 and 414013025421206.

It is not a weakly prime, because it can be changed into another prime (414013025421041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207006512710620 + 207006512710621.

It is an arithmetic number, because the mean of its divisors is an integer number (207006512710621).

Almost surely, 2414013025421241 is an apocalyptic number.

It is an amenable number.

414013025421241 is a deficient number, since it is larger than the sum of its proper divisors (1).

414013025421241 is an equidigital number, since it uses as much as digits as its factorization.

414013025421241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30720, while the sum is 34.

Adding to 414013025421241 its reverse (142124520310414), we get a palindrome (556137545731655).

The spelling of 414013025421241 in words is "four hundred fourteen trillion, thirteen billion, twenty-five million, four hundred twenty-one thousand, two hundred forty-one".