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41404304040401 is a prime number
BaseRepresentation
bin10010110101000001100001…
…10101011010000111010001
312102121012202010201201021002
421122200300311122013101
520411332003313243101
6224020512533311345
711502235152325361
oct1132406065320721
9172535663651232
1041404304040401
111221351524a645
124788521795555
131a14541aa6bb3
14a31d9c5809a1
154bc04ab5cd6b
hex25a830d5a1d1

41404304040401 has 2 divisors, whose sum is σ = 41404304040402. Its totient is φ = 41404304040400.

The previous prime is 41404304040383. The next prime is 41404304040413. The reversal of 41404304040401 is 10404040340414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26502573244225 + 14901730796176 = 5148065^2 + 3860276^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41404304040401 is a prime.

It is a super-3 number, since 3×414043040404013 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (41404300040401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20702152020200 + 20702152020201.

It is an arithmetic number, because the mean of its divisors is an integer number (20702152020201).

Almost surely, 241404304040401 is an apocalyptic number.

It is an amenable number.

41404304040401 is a deficient number, since it is larger than the sum of its proper divisors (1).

41404304040401 is an equidigital number, since it uses as much as digits as its factorization.

41404304040401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12288, while the sum is 29.

Adding to 41404304040401 its reverse (10404040340414), we get a palindrome (51808344380815).

The spelling of 41404304040401 in words is "forty-one trillion, four hundred four billion, three hundred four million, forty thousand, four hundred one".