Base | Representation |
---|---|
bin | 111100010000110011111… |
… | …101000111000110000011 |
3 | 112122220012202021200000220 |
4 | 330100303331013012003 |
5 | 1020322204323144303 |
6 | 12450241131314123 |
7 | 605123203214211 |
oct | 74206375070603 |
9 | 15586182250026 |
10 | 4141220131203 |
11 | 1357310891401 |
12 | 56a71a2ab943 |
13 | 2406913acc4c |
14 | 104616a1bcb1 |
15 | 72ac8d92053 |
hex | 3c433f47183 |
4141220131203 has 4 divisors (see below), whose sum is σ = 5521626841608. Its totient is φ = 2760813420800.
The previous prime is 4141220131199. The next prime is 4141220131231. The reversal of 4141220131203 is 3021310221414.
4141220131203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4141220131203 - 22 = 4141220131199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4141220141203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 690203355198 + ... + 690203355203.
It is an arithmetic number, because the mean of its divisors is an integer number (1380406710402).
Almost surely, 24141220131203 is an apocalyptic number.
4141220131203 is a deficient number, since it is larger than the sum of its proper divisors (1380406710405).
4141220131203 is a wasteful number, since it uses less digits than its factorization.
4141220131203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1380406710404.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 4141220131203 its reverse (3021310221414), we get a palindrome (7162530352617).
The spelling of 4141220131203 in words is "four trillion, one hundred forty-one billion, two hundred twenty million, one hundred thirty-one thousand, two hundred three".
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