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41420544354113 is a prime number
BaseRepresentation
bin10010110101011111110001…
…10101010010011101000001
312102122202122221202010111112
421122233320311102131001
520412113233323312423
6224032200235453105
711503351462605641
oct1132577065223501
9172582587663445
1041420544354113
111221a399502711
12478b6b45b7195
131a15c2c590992
14a32a9d3ca521
154bc69b7c2a78
hex25abf8d52741

41420544354113 has 2 divisors, whose sum is σ = 41420544354114. Its totient is φ = 41420544354112.

The previous prime is 41420544354023. The next prime is 41420544354151. The reversal of 41420544354113 is 31145344502414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35796683879089 + 5623860475024 = 5983033^2 + 2371468^2 .

It is a cyclic number.

It is not a de Polignac number, because 41420544354113 - 238 = 41145666447169 is a prime.

It is a super-2 number, since 2×414205443541132 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41420544374113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20710272177056 + 20710272177057.

It is an arithmetic number, because the mean of its divisors is an integer number (20710272177057).

Almost surely, 241420544354113 is an apocalyptic number.

It is an amenable number.

41420544354113 is a deficient number, since it is larger than the sum of its proper divisors (1).

41420544354113 is an equidigital number, since it uses as much as digits as its factorization.

41420544354113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 41420544354113 its reverse (31145344502414), we get a palindrome (72565888856527).

The spelling of 41420544354113 in words is "forty-one trillion, four hundred twenty billion, five hundred forty-four million, three hundred fifty-four thousand, one hundred thirteen".