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414243011131 = 2683154395457
BaseRepresentation
bin1100000011100101100…
…11101011101000111011
31110121020022022022011121
412001302303223220323
523241332202324011
6514144533210111
741633220332545
oct6016263535073
91417208268147
10414243011131
1114a752420484
1268349190937
13300a83b3791
1416099a56695
15ab9702ee71
hex6072ceba3b

414243011131 has 4 divisors (see below), whose sum is σ = 414397409272. Its totient is φ = 414088612992.

The previous prime is 414243011129. The next prime is 414243011141. The reversal of 414243011131 is 131110342414.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 414243011131 - 21 = 414243011129 is a prime.

It is a super-2 number, since 2×4142430111312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 414243011096 and 414243011105.

It is not an unprimeable number, because it can be changed into a prime (414243011141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77195046 + ... + 77200411.

It is an arithmetic number, because the mean of its divisors is an integer number (103599352318).

Almost surely, 2414243011131 is an apocalyptic number.

414243011131 is a deficient number, since it is larger than the sum of its proper divisors (154398141).

414243011131 is a wasteful number, since it uses less digits than its factorization.

414243011131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154398140.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 414243011131 its reverse (131110342414), we get a palindrome (545353353545).

The spelling of 414243011131 in words is "four hundred fourteen billion, two hundred forty-three million, eleven thousand, one hundred thirty-one".

Divisors: 1 2683 154395457 414243011131