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4143000141011 = 12210613392951
BaseRepresentation
bin111100010010011110000…
…011010011110011010011
3112200001210210200112110002
4330102132003103303103
51020334331014003021
612451133515200215
7605215256103164
oct74223603236323
915601723615402
104143000141011
111358044632096
1256ab3644606b
132408b60c11a4
141047451ad76b
1572b8029c50b
hex3c49e0d3cd3

4143000141011 has 4 divisors (see below), whose sum is σ = 4143004755024. Its totient is φ = 4142995527000.

The previous prime is 4143000141001. The next prime is 4143000141013. The reversal of 4143000141011 is 1101410003414.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4143000141011 is a prime.

It is a super-3 number, since 3×41430001410113 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4143000141013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 475415 + ... + 2917536.

It is an arithmetic number, because the mean of its divisors is an integer number (1035751188756).

Almost surely, 24143000141011 is an apocalyptic number.

4143000141011 is a deficient number, since it is larger than the sum of its proper divisors (4614013).

4143000141011 is a wasteful number, since it uses less digits than its factorization.

4143000141011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4614012.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 4143000141011 its reverse (1101410003414), we get a palindrome (5244410144425).

The spelling of 4143000141011 in words is "four trillion, one hundred forty-three billion, one hundred forty-one thousand, eleven".

Divisors: 1 1221061 3392951 4143000141011