41431213414113 has 4 divisors (see below), whose sum is σ = 55241617885488. Its totient is φ = 27620808942740.

The previous prime is 41431213414111. The next prime is 41431213414153. The reversal of 41431213414113 is 31141431213414.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41431213414113 - 2¹ = 41431213414111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (41431213414111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6905202235683 + ... + 6905202235688.

It is an arithmetic number, because the mean of its divisors is an integer number (13810404471372).

Almost surely, 2^{41431213414113} is an apocalyptic number.

It is an amenable number.

41431213414113 is a deficient number, since it is larger than the sum of its proper divisors (13810404471375).

41431213414113 is a wasteful number, since it uses less digits than its factorization.

41431213414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13810404471374.

The product of its digits is 13824, while the sum is 33.

Adding to 41431213414113 its reverse (31141431213414), we get a palindrome (72572644627527).

The spelling of 41431213414113 in words is "forty-one trillion, four hundred thirty-one billion, two hundred thirteen million, four hundred fourteen thousand, one hundred thirteen".