Base | Representation |
---|---|
bin | 1100000011110000000… |
… | …11010111101111101111 |
3 | 1110121110102220002222010 |
4 | 12001320003113233233 |
5 | 23242022214310111 |
6 | 514201355252303 |
7 | 41635336322241 |
oct | 6017003275757 |
9 | 1417412802863 |
10 | 414331010031 |
11 | 14a798065344 |
12 | 6837274a093 |
13 | 300c06b4933 |
14 | 160a7602091 |
15 | ab9eb13aa6 |
hex | 60780d7bef |
414331010031 has 32 divisors (see below), whose sum is σ = 580132046592. Its totient is φ = 262776234240.
The previous prime is 414331010029. The next prime is 414331010099. The reversal of 414331010031 is 130010133414.
It is not a de Polignac number, because 414331010031 - 21 = 414331010029 is a prime.
It is a super-2 number, since 2×4143310100312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (414331012031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 867636 + ... + 1257558.
It is an arithmetic number, because the mean of its divisors is an integer number (18129126456).
Almost surely, 2414331010031 is an apocalyptic number.
414331010031 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
414331010031 is a deficient number, since it is larger than the sum of its proper divisors (165801036561).
414331010031 is a wasteful number, since it uses less digits than its factorization.
414331010031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 390183.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 414331010031 its reverse (130010133414), we get a palindrome (544341143445).
The spelling of 414331010031 in words is "four hundred fourteen billion, three hundred thirty-one million, ten thousand, thirty-one".
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