Base | Representation |
---|---|
bin | 111100010010110111110… |
… | …100000010000111001011 |
3 | 112200002220220221201111121 |
4 | 330102313310002013023 |
5 | 1020341222140002021 |
6 | 12451244434540111 |
7 | 605232054550222 |
oct | 74226764020713 |
9 | 15602826851447 |
10 | 4143432344011 |
11 | 13582465a2654 |
12 | 56b037137637 |
13 | 2409547c93cc |
14 | 104786757cb9 |
15 | 72ba81c2741 |
hex | 3c4b7d021cb |
4143432344011 has 2 divisors, whose sum is σ = 4143432344012. Its totient is φ = 4143432344010.
The previous prime is 4143432343961. The next prime is 4143432344041. The reversal of 4143432344011 is 1104432343414.
4143432344011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4143432344011 - 211 = 4143432341963 is a prime.
It is not a weakly prime, because it can be changed into another prime (4143432344041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071716172005 + 2071716172006.
It is an arithmetic number, because the mean of its divisors is an integer number (2071716172006).
Almost surely, 24143432344011 is an apocalyptic number.
4143432344011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4143432344011 is an equidigital number, since it uses as much as digits as its factorization.
4143432344011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 4143432344011 its reverse (1104432343414), we get a palindrome (5247864687425).
The spelling of 4143432344011 in words is "four trillion, one hundred forty-three billion, four hundred thirty-two million, three hundred forty-four thousand, eleven".
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