Base | Representation |
---|---|
bin | 1100000011111000010… |
… | …11010100110100000001 |
3 | 1110121122021002112021221 |
4 | 12001330023110310001 |
5 | 23242142423012113 |
6 | 514212310315041 |
7 | 41640136421104 |
oct | 6017413246401 |
9 | 1417567075257 |
10 | 414400204033 |
11 | 14a823125872 |
12 | 68391958a81 |
13 | 30101b3062a |
14 | 160b289473b |
15 | aba5c3098d |
hex | 607c2d4d01 |
414400204033 has 2 divisors, whose sum is σ = 414400204034. Its totient is φ = 414400204032.
The previous prime is 414400203977. The next prime is 414400204039. The reversal of 414400204033 is 330402004414.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 414179770624 + 220433409 = 643568^2 + 14847^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-414400204033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 414400203989 and 414400204007.
It is not a weakly prime, because it can be changed into another prime (414400204039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207200102016 + 207200102017.
It is an arithmetic number, because the mean of its divisors is an integer number (207200102017).
Almost surely, 2414400204033 is an apocalyptic number.
It is an amenable number.
414400204033 is a deficient number, since it is larger than the sum of its proper divisors (1).
414400204033 is an equidigital number, since it uses as much as digits as its factorization.
414400204033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 414400204033 its reverse (330402004414), we get a palindrome (744802208447).
The spelling of 414400204033 in words is "four hundred fourteen billion, four hundred million, two hundred four thousand, thirty-three".
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