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414431252153 is a prime number
BaseRepresentation
bin1100000011111100000…
…01110000111010111001
31110121201102111221022022
412001332001300322321
523242223400032103
6514215340004225
741640664343312
oct6017601607271
91417642457268
10414431252153
1114a839701776
12683a0230675
13301083b16b9
14160b6a57609
15aba8815138
hex607e070eb9

414431252153 has 2 divisors, whose sum is σ = 414431252154. Its totient is φ = 414431252152.

The previous prime is 414431252129. The next prime is 414431252233. The reversal of 414431252153 is 351252134414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 372689493289 + 41741758864 = 610483^2 + 204308^2 .

It is a cyclic number.

It is not a de Polignac number, because 414431252153 - 218 = 414430990009 is a prime.

It is a super-2 number, since 2×4144312521532 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (414431252353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207215626076 + 207215626077.

It is an arithmetic number, because the mean of its divisors is an integer number (207215626077).

Almost surely, 2414431252153 is an apocalyptic number.

It is an amenable number.

414431252153 is a deficient number, since it is larger than the sum of its proper divisors (1).

414431252153 is an equidigital number, since it uses as much as digits as its factorization.

414431252153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 57600, while the sum is 35.

Adding to 414431252153 its reverse (351252134414), we get a palindrome (765683386567).

The spelling of 414431252153 in words is "four hundred fourteen billion, four hundred thirty-one million, two hundred fifty-two thousand, one hundred fifty-three".