Base | Representation |
---|---|
bin | 10010110110001010001010… |
… | …01011100111101111001001 |
3 | 12102201221101211201110202022 |
4 | 21123011011023213233021 |
5 | 20413001334312111403 |
6 | 224050442250414225 |
7 | 11505115416431225 |
oct | 1133050513475711 |
9 | 172657354643668 |
10 | 41443300113353 |
11 | 12229006542406 |
12 | 4793ba5431375 |
13 | 1a18117b75988 |
14 | a33c1b69b785 |
15 | 4bd07e439d38 |
hex | 25b1452e7bc9 |
41443300113353 has 2 divisors, whose sum is σ = 41443300113354. Its totient is φ = 41443300113352.
The previous prime is 41443300113239. The next prime is 41443300113359. The reversal of 41443300113353 is 35331100334414.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40696195733449 + 747104379904 = 6379357^2 + 864352^2 .
It is a cyclic number.
It is not a de Polignac number, because 41443300113353 - 210 = 41443300112329 is a prime.
It is not a weakly prime, because it can be changed into another prime (41443300113359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20721650056676 + 20721650056677.
It is an arithmetic number, because the mean of its divisors is an integer number (20721650056677).
Almost surely, 241443300113353 is an apocalyptic number.
It is an amenable number.
41443300113353 is a deficient number, since it is larger than the sum of its proper divisors (1).
41443300113353 is an equidigital number, since it uses as much as digits as its factorization.
41443300113353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 41443300113353 its reverse (35331100334414), we get a palindrome (76774400447767).
The spelling of 41443300113353 in words is "forty-one trillion, four hundred forty-three billion, three hundred million, one hundred thirteen thousand, three hundred fifty-three".
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