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41443300113353 is a prime number
BaseRepresentation
bin10010110110001010001010…
…01011100111101111001001
312102201221101211201110202022
421123011011023213233021
520413001334312111403
6224050442250414225
711505115416431225
oct1133050513475711
9172657354643668
1041443300113353
1112229006542406
124793ba5431375
131a18117b75988
14a33c1b69b785
154bd07e439d38
hex25b1452e7bc9

41443300113353 has 2 divisors, whose sum is σ = 41443300113354. Its totient is φ = 41443300113352.

The previous prime is 41443300113239. The next prime is 41443300113359. The reversal of 41443300113353 is 35331100334414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40696195733449 + 747104379904 = 6379357^2 + 864352^2 .

It is a cyclic number.

It is not a de Polignac number, because 41443300113353 - 210 = 41443300112329 is a prime.

It is not a weakly prime, because it can be changed into another prime (41443300113359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20721650056676 + 20721650056677.

It is an arithmetic number, because the mean of its divisors is an integer number (20721650056677).

Almost surely, 241443300113353 is an apocalyptic number.

It is an amenable number.

41443300113353 is a deficient number, since it is larger than the sum of its proper divisors (1).

41443300113353 is an equidigital number, since it uses as much as digits as its factorization.

41443300113353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 41443300113353 its reverse (35331100334414), we get a palindrome (76774400447767).

The spelling of 41443300113353 in words is "forty-one trillion, four hundred forty-three billion, three hundred million, one hundred thirteen thousand, three hundred fifty-three".