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4144401038081 is a prime number
BaseRepresentation
bin111100010011110001100…
…011010011101100000001
3112200012102102201110221202
4330103301203103230001
51020400213131204311
612451524521230545
7605265056403203
oct74236143235401
915605372643852
104144401038081
1113586a3383867
1256b267632455
13240a7a3c5075
14104839276773
1572c1326ce3b
hex3c4f18d3b01

4144401038081 has 2 divisors, whose sum is σ = 4144401038082. Its totient is φ = 4144401038080.

The previous prime is 4144401038059. The next prime is 4144401038087. The reversal of 4144401038081 is 1808301044414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2802142081600 + 1342258956481 = 1673960^2 + 1158559^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4144401038081 is a prime.

It is a super-2 number, since 2×41444010380812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4144401038087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072200519040 + 2072200519041.

It is an arithmetic number, because the mean of its divisors is an integer number (2072200519041).

Almost surely, 24144401038081 is an apocalyptic number.

It is an amenable number.

4144401038081 is a deficient number, since it is larger than the sum of its proper divisors (1).

4144401038081 is an equidigital number, since it uses as much as digits as its factorization.

4144401038081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 49152, while the sum is 38.

The spelling of 4144401038081 in words is "four trillion, one hundred forty-four billion, four hundred one million, thirty-eight thousand, eighty-one".