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4145311344241 is a prime number
BaseRepresentation
bin111100010100100111110…
…011110110011001110001
3112200021202212121211020201
4330110213303312121301
51020404044201003431
612452155120235201
7605326452025054
oct74244763663161
915607685554221
104145311344241
111359020205301
1256b48046bb01
13240b93b89772
141048c4116a9b
1572c68133461
hex3c527cf6671

4145311344241 has 2 divisors, whose sum is σ = 4145311344242. Its totient is φ = 4145311344240.

The previous prime is 4145311344233. The next prime is 4145311344281. The reversal of 4145311344241 is 1424431135414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3819132147600 + 326179196641 = 1954260^2 + 571121^2 .

It is a cyclic number.

It is not a de Polignac number, because 4145311344241 - 23 = 4145311344233 is a prime.

It is a super-2 number, since 2×41453113442412 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4145311344241.

It is not a weakly prime, because it can be changed into another prime (4145311344221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072655672120 + 2072655672121.

It is an arithmetic number, because the mean of its divisors is an integer number (2072655672121).

Almost surely, 24145311344241 is an apocalyptic number.

It is an amenable number.

4145311344241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4145311344241 is an equidigital number, since it uses as much as digits as its factorization.

4145311344241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 92160, while the sum is 37.

Adding to 4145311344241 its reverse (1424431135414), we get a palindrome (5569742479655).

The spelling of 4145311344241 in words is "four trillion, one hundred forty-five billion, three hundred eleven million, three hundred forty-four thousand, two hundred forty-one".