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41503213133113 is a prime number
BaseRepresentation
bin10010110111111001110000…
…10001101001110100111001
312102221200001021122020001011
421123330320101221310321
520414442040030224423
6224134151330353521
711512336211621224
oct1133747021516471
9172850037566034
1041503213133113
1112251460910976
1247a372612b8a1
131a2097559a564
14a36aa278c5bb
154be8d920ab0d
hex25bf38469d39

41503213133113 has 2 divisors, whose sum is σ = 41503213133114. Its totient is φ = 41503213133112.

The previous prime is 41503213133047. The next prime is 41503213133131. The reversal of 41503213133113 is 31133131230514.

Together with next prime (41503213133131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39877860971664 + 1625352161449 = 6314892^2 + 1274893^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41503213133113 is a prime.

It is not a weakly prime, because it can be changed into another prime (41503213133813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20751606566556 + 20751606566557.

It is an arithmetic number, because the mean of its divisors is an integer number (20751606566557).

Almost surely, 241503213133113 is an apocalyptic number.

It is an amenable number.

41503213133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

41503213133113 is an equidigital number, since it uses as much as digits as its factorization.

41503213133113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 41503213133113 its reverse (31133131230514), we get a palindrome (72636344363627).

The spelling of 41503213133113 in words is "forty-one trillion, five hundred three billion, two hundred thirteen million, one hundred thirty-three thousand, one hundred thirteen".