41507131 has 2 divisors, whose sum is σ = 41507132. Its totient is φ = 41507130.

The previous prime is 41507093. The next prime is 41507161. The reversal of 41507131 is 13170514.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41507131 - 2¹³ = 41498939 is a prime.

It is a super-2 number, since 2×41507131² = 3445683847702322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (41507161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20753565 + 20753566.

It is an arithmetic number, because the mean of its divisors is an integer number (20753566).

Almost surely, 2^41507131 is an apocalyptic number.

41507131 is a deficient number, since it is larger than the sum of its proper divisors (1).

41507131 is an equidigital number, since it uses as much as digits as its factorization.

41507131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 22.

The square root of 41507131 is about 6442.6028125285. The cubic root of 41507131 is about 346.2376078489.

Adding to 41507131 its reverse (13170514), we get a palindrome (54677645).

The spelling of 41507131 in words is "forty-one million, five hundred seven thousand, one hundred thirty-one".