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41531022241 is a prime number
BaseRepresentation
bin100110101011011100…
…010001101110100001
310222012100221112011221
4212223130101232201
51140023420202431
631025025535041
73000114602332
oct465334215641
9128170845157
1041531022241
11166821a7785
1280707a4481
133bbb316b97
14201da68289
15113110d111
hex9ab711ba1

41531022241 has 2 divisors, whose sum is σ = 41531022242. Its totient is φ = 41531022240.

The previous prime is 41531022167. The next prime is 41531022251. The reversal of 41531022241 is 14222013514.

41531022241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40211879841 + 1319142400 = 200529^2 + 36320^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41531022241 is a prime.

It is not a weakly prime, because it can be changed into another prime (41531022251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20765511120 + 20765511121.

It is an arithmetic number, because the mean of its divisors is an integer number (20765511121).

Almost surely, 241531022241 is an apocalyptic number.

It is an amenable number.

41531022241 is a deficient number, since it is larger than the sum of its proper divisors (1).

41531022241 is an equidigital number, since it uses as much as digits as its factorization.

41531022241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 41531022241 its reverse (14222013514), we get a palindrome (55753035755).

The spelling of 41531022241 in words is "forty-one billion, five hundred thirty-one million, twenty-two thousand, two hundred forty-one".