Base | Representation |
---|---|
bin | 10010111000110101000000… |
… | …11110111111001100100011 |
3 | 12110001201011101120222211201 |
4 | 21130122200132333030203 |
5 | 20421002213203330201 |
6 | 224200532211422031 |
7 | 11514543445523044 |
oct | 1134324036771443 |
9 | 173051141528751 |
10 | 41535026230051 |
11 | 122639a6544522 |
12 | 47a99242b4917 |
13 | 1a23975489a83 |
14 | a3843d91c8cb |
15 | 4c064c0c8801 |
hex | 25c6a07bf323 |
41535026230051 has 4 divisors (see below), whose sum is σ = 41538632025600. Its totient is φ = 41531420434504.
The previous prime is 41535026230013. The next prime is 41535026230097. The reversal of 41535026230051 is 15003262053514.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41535026230051 - 215 = 41535026197283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41535026230001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1802880496 + ... + 1802903533.
It is an arithmetic number, because the mean of its divisors is an integer number (10384658006400).
Almost surely, 241535026230051 is an apocalyptic number.
41535026230051 is a deficient number, since it is larger than the sum of its proper divisors (3605795549).
41535026230051 is a wasteful number, since it uses less digits than its factorization.
41535026230051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3605795548.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 41535026230051 its reverse (15003262053514), we get a palindrome (56538288283565).
The spelling of 41535026230051 in words is "forty-one trillion, five hundred thirty-five billion, twenty-six million, two hundred thirty thousand, fifty-one".
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