Base | Representation |
---|---|
bin | 10010111000110111101001… |
… | …10111110001011011011011 |
3 | 12110001211211001122020111011 |
4 | 21130123310313301123123 |
5 | 20421013113123412103 |
6 | 224201324504514351 |
7 | 11514623516503231 |
oct | 1134336467613333 |
9 | 173054731566434 |
10 | 41536442013403 |
11 | 12264562733507 |
12 | 47aa05a47b9b7 |
13 | 1a23b3c8a35bc |
14 | a3853597c951 |
15 | 4c06d1539d6d |
hex | 25c6f4df16db |
41536442013403 has 2 divisors, whose sum is σ = 41536442013404. Its totient is φ = 41536442013402.
The previous prime is 41536442013383. The next prime is 41536442013421. The reversal of 41536442013403 is 30431024463514.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41536442013403 - 213 = 41536442005211 is a prime.
It is not a weakly prime, because it can be changed into another prime (41536442013433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20768221006701 + 20768221006702.
It is an arithmetic number, because the mean of its divisors is an integer number (20768221006702).
Almost surely, 241536442013403 is an apocalyptic number.
41536442013403 is a deficient number, since it is larger than the sum of its proper divisors (1).
41536442013403 is an equidigital number, since it uses as much as digits as its factorization.
41536442013403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 40.
Adding to 41536442013403 its reverse (30431024463514), we get a palindrome (71967466476917).
The spelling of 41536442013403 in words is "forty-one trillion, five hundred thirty-six billion, four hundred forty-two million, thirteen thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •