Base | Representation |
---|---|
bin | 1111011110010110… |
… | …0101011101101011 |
3 | 101201111011011212020 |
4 | 3313211211131223 |
5 | 32001334401011 |
6 | 1524102515523 |
7 | 204635634231 |
oct | 36745453553 |
9 | 11644134766 |
10 | 4153825131 |
11 | 18417a9335 |
12 | 97b135ba3 |
13 | 51275c6c1 |
14 | 2b5956951 |
15 | 194a0d006 |
hex | f796576b |
4153825131 has 4 divisors (see below), whose sum is σ = 5538433512. Its totient is φ = 2769216752.
The previous prime is 4153825111. The next prime is 4153825141. The reversal of 4153825131 is 1315283514.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4153825131 - 27 = 4153825003 is a prime.
It is a super-2 number, since 2×41538251312 = 34508526437854334322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4153825092 and 4153825101.
It is not an unprimeable number, because it can be changed into a prime (4153825111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 692304186 + ... + 692304191.
It is an arithmetic number, because the mean of its divisors is an integer number (1384608378).
Almost surely, 24153825131 is an apocalyptic number.
4153825131 is a deficient number, since it is larger than the sum of its proper divisors (1384608381).
4153825131 is a wasteful number, since it uses less digits than its factorization.
4153825131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1384608380.
The product of its digits is 14400, while the sum is 33.
The square root of 4153825131 is about 64450.1755699703. The cubic root of 4153825131 is about 1607.4941576298.
The spelling of 4153825131 in words is "four billion, one hundred fifty-three million, eight hundred twenty-five thousand, one hundred thirty-one".
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