Base | Representation |
---|---|
bin | 1100000101110010101… |
… | …00100111101111100001 |
3 | 1110201021202101221211120 |
4 | 12002321110213233201 |
5 | 23301243032113131 |
6 | 514502154002453 |
7 | 42004434112521 |
oct | 6027124475741 |
9 | 1421252357746 |
10 | 415426051041 |
11 | 1501aa1a2911 |
12 | 68619416429 |
13 | 3023651a3b1 |
14 | 1616cc0d681 |
15 | ac15d1a496 |
hex | 60b9527be1 |
415426051041 has 4 divisors (see below), whose sum is σ = 553901401392. Its totient is φ = 276950700692.
The previous prime is 415426051021. The next prime is 415426051099. The reversal of 415426051041 is 140150624514.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 415426051041 - 25 = 415426051009 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 415426050993 and 415426051011.
It is not an unprimeable number, because it can be changed into a prime (415426051021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69237675171 + ... + 69237675176.
It is an arithmetic number, because the mean of its divisors is an integer number (138475350348).
Almost surely, 2415426051041 is an apocalyptic number.
It is an amenable number.
415426051041 is a deficient number, since it is larger than the sum of its proper divisors (138475350351).
415426051041 is a wasteful number, since it uses less digits than its factorization.
415426051041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138475350350.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 415426051041 its reverse (140150624514), we get a palindrome (555576675555).
The spelling of 415426051041 in words is "four hundred fifteen billion, four hundred twenty-six million, fifty-one thousand, forty-one".
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