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41543234333473 is a prime number
BaseRepresentation
bin10010111001000100010011…
…01110011010101100100001
312110002111100102120211222011
421130202021232122230201
520421121020442132343
6224204410503512521
711515254034330525
oct1134421156325441
9173074312524864
1041543234333473
111226742882a074
1247ab435158741
131a24682b636c2
14a389bbab7d85
154c097c9ce29d
hex25c889b9ab21

41543234333473 has 2 divisors, whose sum is σ = 41543234333474. Its totient is φ = 41543234333472.

The previous prime is 41543234333347. The next prime is 41543234333501. The reversal of 41543234333473 is 37433343234514.

Together with previous prime (41543234333347) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39019911614464 + 2523322719009 = 6246592^2 + 1588497^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41543234333473 is a prime.

It is not a weakly prime, because it can be changed into another prime (41543235333473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20771617166736 + 20771617166737.

It is an arithmetic number, because the mean of its divisors is an integer number (20771617166737).

Almost surely, 241543234333473 is an apocalyptic number.

It is an amenable number.

41543234333473 is a deficient number, since it is larger than the sum of its proper divisors (1).

41543234333473 is an equidigital number, since it uses as much as digits as its factorization.

41543234333473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13063680, while the sum is 49.

Adding to 41543234333473 its reverse (37433343234514), we get a palindrome (78976577567987).

The spelling of 41543234333473 in words is "forty-one trillion, five hundred forty-three billion, two hundred thirty-four million, three hundred thirty-three thousand, four hundred seventy-three".