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41552131454017 is a prime number
BaseRepresentation
bin10010111001010100111000…
…00010001111010001000001
312110010100022111002101220021
421130222130002033101001
520421242231123012032
6224212441412013441
711516020360524502
oct1134523402172101
9173110274071807
1041552131454017
1112270183a42458
1247b10b8901281
131a25470202682
14a391c358cba9
154c0cedb38097
hex25ca9c08f441

41552131454017 has 2 divisors, whose sum is σ = 41552131454018. Its totient is φ = 41552131454016.

The previous prime is 41552131453993. The next prime is 41552131454101. The reversal of 41552131454017 is 71045413125514.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36609264212481 + 4942867241536 = 6050559^2 + 2223256^2 .

It is a cyclic number.

It is not a de Polignac number, because 41552131454017 - 211 = 41552131451969 is a prime.

It is not a weakly prime, because it can be changed into another prime (41552131454417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20776065727008 + 20776065727009.

It is an arithmetic number, because the mean of its divisors is an integer number (20776065727009).

Almost surely, 241552131454017 is an apocalyptic number.

It is an amenable number.

41552131454017 is a deficient number, since it is larger than the sum of its proper divisors (1).

41552131454017 is an equidigital number, since it uses as much as digits as its factorization.

41552131454017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336000, while the sum is 43.

The spelling of 41552131454017 in words is "forty-one trillion, five hundred fifty-two billion, one hundred thirty-one million, four hundred fifty-four thousand, seventeen".