Base | Representation |
---|---|
bin | 10010111001010100111000… |
… | …00010001111010001000001 |
3 | 12110010100022111002101220021 |
4 | 21130222130002033101001 |
5 | 20421242231123012032 |
6 | 224212441412013441 |
7 | 11516020360524502 |
oct | 1134523402172101 |
9 | 173110274071807 |
10 | 41552131454017 |
11 | 12270183a42458 |
12 | 47b10b8901281 |
13 | 1a25470202682 |
14 | a391c358cba9 |
15 | 4c0cedb38097 |
hex | 25ca9c08f441 |
41552131454017 has 2 divisors, whose sum is σ = 41552131454018. Its totient is φ = 41552131454016.
The previous prime is 41552131453993. The next prime is 41552131454101. The reversal of 41552131454017 is 71045413125514.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36609264212481 + 4942867241536 = 6050559^2 + 2223256^2 .
It is a cyclic number.
It is not a de Polignac number, because 41552131454017 - 211 = 41552131451969 is a prime.
It is not a weakly prime, because it can be changed into another prime (41552131454417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20776065727008 + 20776065727009.
It is an arithmetic number, because the mean of its divisors is an integer number (20776065727009).
Almost surely, 241552131454017 is an apocalyptic number.
It is an amenable number.
41552131454017 is a deficient number, since it is larger than the sum of its proper divisors (1).
41552131454017 is an equidigital number, since it uses as much as digits as its factorization.
41552131454017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336000, while the sum is 43.
The spelling of 41552131454017 in words is "forty-one trillion, five hundred fifty-two billion, one hundred thirty-one million, four hundred fifty-four thousand, seventeen".
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